Solve following using suitable identities : (99)^{3}

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2. Polynomials

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Evaluate the following using suitable identities : $(99)^{3}$

A

$970270 $

B

$979270 $

C

$990277 $

D

$970299 $

Solution

We have

$99=100-1$

$\therefore \quad 99^{3} =(100-1)^{3}=100^{3}-1^{3}-3(100)(1)(100-1) $

$=1000000-1-300(100-1)=1000000-1-30000+300 $

$=1000300-30001=970299 $

Standard 9

Mathematics

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